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100x^2-225x+81=0
a = 100; b = -225; c = +81;
Δ = b2-4ac
Δ = -2252-4·100·81
Δ = 18225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{18225}=135$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-225)-135}{2*100}=\frac{90}{200} =9/20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-225)+135}{2*100}=\frac{360}{200} =1+4/5 $
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